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gfse: create a new concrete syntax by copying an existing one

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When adding a new concrete syntax to a grammar, the currently open concrete
syntax will be copied. If the abstract syntax is currently open, the new
concrete syntax will start out empty.
This commit is contained in:
hallgren
2011-03-07 17:52:15 +00:00
parent cfb5f6eb7e
commit 62c85f1bb6
3 changed files with 48 additions and 17 deletions
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29
src/editor/simple/editor.js
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@@ -164,6 +164,10 @@ function add_concrete(g,el) {
list.push(li([a(jsurl("add_concrete2("+g.index+",'"+c+"')"),
[text(l.name)])]));
}
var from= g.current>0
? "a copy of "+langname[g.concretes[g.current-1].langcode]
:"scratch";
file.appendChild(p(text("You are about to create a new concrete syntax by starting from "+from+".")));
file.appendChild(p(text("Pick a language for the new concrete syntax:")));
file.appendChild(node("ul",{},list));
}
@@ -175,11 +179,26 @@ function new_concrete(code) {
function add_concrete2(ix,code) {
var g=local.get(ix);
var cs=g.concretes;
var i;
for(var i=0;i<cs.length;i++) if(cs[i].langcode==code) break;
if(i==cs.length) cs.push(new_concrete(code))
save_grammar(g);
open_concrete(g,i);
var ci;
for(var ci=0;ci<cs.length;ci++) if(cs[ci].langcode==code) break;
if(ci==cs.length) {
if(g.current>0) {
cs.push(cs[g.current-1]); // old and new are shared at this point
save_grammar(g); // serialization loses sharing
g=local.get(ix); // old and new are separate now
var oldcode=cs[g.current-1].langcode;
var cnc=g.concretes[ci];
cnc.langcode=code;
for(var oi in cnc.opens)
for(var li in rgl_modules)
if(cnc.opens[oi]==rgl_modules[li]+oldcode)
cnc.opens[oi]=rgl_modules[li]+code;
}
else
cs.push(new_concrete(code))
save_grammar(g);
}
open_concrete(g,ci);
}
function open_abstract(g) { g.current=0; reload_grammar(g); }