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work-around in Tree.expr2tree to make Paraphrase work

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aarne
2010-12-14 14:36:05 +00:00
parent a8a3c62f60
commit e7fbe756a3
2 changed files with 6 additions and 4 deletions
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7
src/runtime/haskell/PGF/Paraphrase.hs
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@@ -24,7 +24,7 @@ import qualified Data.Map as Map
import Debug.Trace ----
paraphrase :: PGF -> Expr -> [Expr]
paraphrase pgf = nub . paraphraseN 2 pgf
paraphrase pgf t = nub (paraphraseN 2 pgf t)
paraphraseN :: Int -> PGF -> Expr -> [Expr]
paraphraseN i pgf = map tree2expr . paraphraseN' i pgf . expr2tree
@@ -53,8 +53,9 @@ fromDef pgf t@(Fun f ts) = defDown t ++ defUp t where
isClosed d || (length equs == 1 && isLinear d)]
equss = [(f,[(Fun f (map patt2tree ps), expr2tree d) | (Equ ps d) <- eqs]) |
(f,(_,_,Just eqs,_)) <- Map.assocs (funs (abstract pgf)), not (null eqs)]
(f,(_,_,Just eqs,_)) <- Map.assocs (funs (abstract pgf)), not (null eqs)]
---- AR 14/12/2010: (expr2tree d) fails unless we send the variable list from ps in eqs;
---- cf. PGF.Tree.expr2tree
trequ s f e = True ----trace (s ++ ": " ++ show f ++ " " ++ show e) True
subst :: Subst -> Tree -> Tree