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52 lines
1.7 KiB
Haskell
52 lines
1.7 KiB
Haskell
module RemoveLiT (removeLiT) where
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import Grammar
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import Ident
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import Modules
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import Macros
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import Lookup
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import Operations
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import Monad
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-- remove obsolete (Lin C) expressions before doing anything else. AR 21/6/2003
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-- What the program does is replace the occurrences of Lin C with the actual
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-- definition T given in lincat C = T ; with {s : Str} if no lincat is found.
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-- The procedule is uncertain, if T contains another Lin.
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removeLiT :: SourceGrammar -> Err SourceGrammar
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removeLiT gr = liftM MGrammar $ mapM (remlModule gr) (modules gr)
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remlModule :: SourceGrammar -> (Ident,SourceModInfo) -> Err (Ident,SourceModInfo)
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remlModule gr mi@(name,mod) = case mod of
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ModMod (Module mt st fs me ops js) -> do
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js1 <- mapMTree (remlResInfo gr) js
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let mod2 = ModMod $ Module mt st fs me ops js1
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return $ (name,mod2)
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_ -> return mi
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remlResInfo :: SourceGrammar -> (Ident,Info) -> Err (Ident,Info)
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remlResInfo gr mi@(i,info) = case info of
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ResOper pty ptr -> liftM ((,) i) $ liftM2 ResOper (ren pty) (ren ptr)
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CncCat pty ptr ppr -> liftM ((,) i) $ liftM3 CncCat (ren pty) (ren ptr) (ren ppr)
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CncFun mt ptr ppr -> liftM ((,) i) $ liftM2 (CncFun mt) (ren ptr) (ren ppr)
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_ -> return mi
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where
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ren = remlPerh gr
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remlPerh gr pt = case pt of
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Yes t -> liftM Yes $ remlTerm gr t
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_ -> return pt
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remlTerm :: SourceGrammar -> Term -> Err Term
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remlTerm gr trm = case trm of
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LiT c -> look c >>= remlTerm gr
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_ -> composOp (remlTerm gr) trm
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where
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look c = err (const $ return defLinType) return $ lookupLincat gr m c
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m = case [cnc | (cnc,ModMod m) <- modules gr, isModCnc m] of
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cnc:_ -> cnc -- actually there is always exactly one
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_ -> zIdent "CNC"
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