fix parsing of multiple folded instructions in if predicate expression

This commit is contained in:
Ilya Rezvov
2018-04-24 16:12:52 -07:00
parent 081d6ded2a
commit 9d14c233c5
+13 -10
View File
@@ -795,19 +795,22 @@ folded_loop1 :: { Maybe Ident -> Instruction }
folded_if_result :: { Maybe Ident -> [Instruction] }
: 'result' valtype ')' '(' folded_then_else {
\ident -> [IfInstr ident [$2] (fst $5) (snd $5)]
\ident ->
let (pred, (trueBranch, falseBranch)) = $5 in
pred ++ [IfInstr ident [$2] trueBranch falseBranch]
}
| 'result' valtype ')' '(' foldedinstr1 '(' folded_then_else {
\ident -> $5 ++ [IfInstr ident [$2] (fst $7) (snd $7)]
| folded_then_else {
\ident ->
let (pred, (trueBranch, falseBranch)) = $1 in
pred ++ [IfInstr ident [] trueBranch falseBranch]
}
| folded_if { $1 }
folded_if :: { Maybe Ident -> [Instruction] }
: folded_then_else { \ident -> [IfInstr ident [] (fst $1) (snd $1)] }
| foldedinstr1 '(' folded_then_else { \ident -> $1 ++ [IfInstr ident [] (fst $3) (snd $3)] }
folded_then_else :: { ([Instruction], [Instruction]) }
: 'then' list(instruction) ')' folded_else { (concat $2, $4)}
folded_then_else :: { ([Instruction], ([Instruction], [Instruction])) }
: 'then' list(instruction) ')' folded_else { ([], (concat $2, $4)) }
| foldedinstr1 '(' folded_then_else {
let (pred, branches) = $3 in
($1 ++ pred, branches)
}
folded_else :: { [Instruction] }
: ')' { [] }