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made the "how old" construction in Chinese more efficient by moving variants to the top level; the resulting rule is the same. This kind of inefficiencies are best found if you compile with the -v option and check for constructors creating unexpectedly many PGF rules.

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aarne
2014-08-24 14:28:48 +00:00
parent 4d4bfbe5ec
commit 67fefa20a5
2 changed files with 2 additions and 2 deletions
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2
examples/phrasebook/WordsChi.gf
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@@ -158,7 +158,7 @@ AWantGo p place = mkCl p.name want_VV (mkVP L.go_V place.name) ;
-- miscellaneous
QWhatName p = lin QS {s = \\_ => p.name.s ++ R.word "贵姓"} ; ---
QWhatAge p = lin QS {s = \\_ => p.name.s ++ (R.word "几岁" | R.word "多大")} ; ---
QWhatAge p = lin QS {s = \\_ => p.name.s ++ R.word "几岁"} | lin QS {s = \\_ => p.name.s ++ R.word "多大"} ; ---
HowMuchCost item = lin QS {s = \\_ => item.s ++ R.word "是多少钱"} ;
ItCost item price = mkCl item (mkV2 "是") price ;

2
lib/src/chinese/ConstructionChi.gf
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@@ -14,7 +14,7 @@ lin
married_Cl x y = mkCl (lin NP x) L.married_A2 (lin NP y) ;
what_name_QCl x = mkQCl whatSg_IP (mkClSlash (lin NP x) (mkV2 (mkV "叫"))) ;
how_old_QCl x = {s = \\_,p,a => x.s ++ (R.word "几岁" | R.word "多大")} ; ----
how_old_QCl x = {s = \\_,p,a => x.s ++ R.word "几岁"} | {s = \\_,p,a => x.s ++ R.word "多大"} ; ----
---- how_far_QCl x = mkQCl (E.IAdvAdv (ss "far")) (lin NP x) ;
-- some more things